4c^2+19c+22=0

Solution for 4c^2+19c+22=0 equation:

Simplifying
4c2 + 19c + 22 = 0

Reorder the terms:
22 + 19c + 4c2 = 0

Solving
22 + 19c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(11 + 4c)(2 + c) = 0

Subproblem 1
Set the factor '(11 + 4c)' equal to zero and attempt to solve:

Simplifying
11 + 4c = 0

Solving
11 + 4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 4c = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 4c = 0 + -11
4c = 0 + -11

Combine like terms: 0 + -11 = -11
4c = -11

Divide each side by '4'.
c = -2.75

Simplifying
c = -2.75
Subproblem 2
Set the factor '(2 + c)' equal to zero and attempt to solve:

Simplifying
2 + c = 0

Solving
2 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + c = 0 + -2
c = 0 + -2

Combine like terms: 0 + -2 = -2
c = -2

Simplifying
c = -2
Solution
c = {-2.75, -2}